Optimal. Leaf size=109 \[ \frac{i d \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{2 b^2}-\frac{d \cot (a+b x)}{2 b^2}-\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{(c+d x) \cot ^2(a+b x)}{2 b}-\frac{d x}{2 b}+\frac{i (c+d x)^2}{2 d} \]
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Rubi [A] time = 0.128258, antiderivative size = 109, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 14, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.5, Rules used = {3720, 3473, 8, 3717, 2190, 2279, 2391} \[ \frac{i d \text{PolyLog}\left (2,e^{2 i (a+b x)}\right )}{2 b^2}-\frac{d \cot (a+b x)}{2 b^2}-\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{(c+d x) \cot ^2(a+b x)}{2 b}-\frac{d x}{2 b}+\frac{i (c+d x)^2}{2 d} \]
Antiderivative was successfully verified.
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Rule 3720
Rule 3473
Rule 8
Rule 3717
Rule 2190
Rule 2279
Rule 2391
Rubi steps
\begin{align*} \int (c+d x) \cot ^3(a+b x) \, dx &=-\frac{(c+d x) \cot ^2(a+b x)}{2 b}+\frac{d \int \cot ^2(a+b x) \, dx}{2 b}-\int (c+d x) \cot (a+b x) \, dx\\ &=\frac{i (c+d x)^2}{2 d}-\frac{d \cot (a+b x)}{2 b^2}-\frac{(c+d x) \cot ^2(a+b x)}{2 b}+2 i \int \frac{e^{2 i (a+b x)} (c+d x)}{1-e^{2 i (a+b x)}} \, dx-\frac{d \int 1 \, dx}{2 b}\\ &=-\frac{d x}{2 b}+\frac{i (c+d x)^2}{2 d}-\frac{d \cot (a+b x)}{2 b^2}-\frac{(c+d x) \cot ^2(a+b x)}{2 b}-\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}+\frac{d \int \log \left (1-e^{2 i (a+b x)}\right ) \, dx}{b}\\ &=-\frac{d x}{2 b}+\frac{i (c+d x)^2}{2 d}-\frac{d \cot (a+b x)}{2 b^2}-\frac{(c+d x) \cot ^2(a+b x)}{2 b}-\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}-\frac{(i d) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{2 i (a+b x)}\right )}{2 b^2}\\ &=-\frac{d x}{2 b}+\frac{i (c+d x)^2}{2 d}-\frac{d \cot (a+b x)}{2 b^2}-\frac{(c+d x) \cot ^2(a+b x)}{2 b}-\frac{(c+d x) \log \left (1-e^{2 i (a+b x)}\right )}{b}+\frac{i d \text{Li}_2\left (e^{2 i (a+b x)}\right )}{2 b^2}\\ \end{align*}
Mathematica [B] time = 6.14359, size = 240, normalized size = 2.2 \[ \frac{d \csc (a) \sec (a) \left (\frac{\tan (a) \left (i \text{PolyLog}\left (2,e^{2 i \left (\tan ^{-1}(\tan (a))+b x\right )}\right )+i b x \left (2 \tan ^{-1}(\tan (a))-\pi \right )-2 \left (\tan ^{-1}(\tan (a))+b x\right ) \log \left (1-e^{2 i \left (\tan ^{-1}(\tan (a))+b x\right )}\right )+2 \tan ^{-1}(\tan (a)) \log \left (\sin \left (\tan ^{-1}(\tan (a))+b x\right )\right )-\pi \log \left (1+e^{-2 i b x}\right )+\pi \log (\cos (b x))\right )}{\sqrt{\tan ^2(a)+1}}+b^2 x^2 e^{i \tan ^{-1}(\tan (a))}\right )}{2 b^2 \sqrt{\sec ^2(a) \left (\sin ^2(a)+\cos ^2(a)\right )}}+\frac{d \csc (a) \sin (b x) \csc (a+b x)}{2 b^2}-\frac{c \left (\cot ^2(a+b x)+2 \log (\tan (a+b x))+2 \log (\cos (a+b x))\right )}{2 b}-\frac{d x \csc ^2(a+b x)}{2 b}-\frac{1}{2} d x^2 \cot (a) \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.161, size = 281, normalized size = 2.6 \begin{align*} -icx+{\frac{2\,idax}{b}}+{\frac{2\,bdx{{\rm e}^{2\,i \left ( bx+a \right ) }}+2\,bc{{\rm e}^{2\,i \left ( bx+a \right ) }}-id{{\rm e}^{2\,i \left ( bx+a \right ) }}+id}{{b}^{2} \left ({{\rm e}^{2\,i \left ( bx+a \right ) }}-1 \right ) ^{2}}}-{\frac{c\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}-1 \right ) }{b}}+2\,{\frac{c\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{b}}-{\frac{c\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}+1 \right ) }{b}}+{\frac{id{a}^{2}}{{b}^{2}}}+{\frac{id{\it polylog} \left ( 2,-{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{2}}}+{\frac{i}{2}}d{x}^{2}-{\frac{d\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ) x}{b}}-{\frac{d\ln \left ( 1-{{\rm e}^{i \left ( bx+a \right ) }} \right ) a}{{b}^{2}}}+{\frac{id{\it polylog} \left ( 2,{{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{2}}}-{\frac{d\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}+1 \right ) x}{b}}+{\frac{ad\ln \left ({{\rm e}^{i \left ( bx+a \right ) }}-1 \right ) }{{b}^{2}}}-2\,{\frac{ad\ln \left ({{\rm e}^{i \left ( bx+a \right ) }} \right ) }{{b}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 1.6957, size = 1133, normalized size = 10.39 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 0.537357, size = 859, normalized size = 7.88 \begin{align*} \frac{4 \, b d x + 4 \, b c +{\left (i \, d \cos \left (2 \, b x + 2 \, a\right ) - i \, d\right )}{\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right )\right ) +{\left (-i \, d \cos \left (2 \, b x + 2 \, a\right ) + i \, d\right )}{\rm Li}_2\left (\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right )\right ) + 2 \,{\left (b c - a d -{\left (b c - a d\right )} \cos \left (2 \, b x + 2 \, a\right )\right )} \log \left (-\frac{1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) + \frac{1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac{1}{2}\right ) + 2 \,{\left (b c - a d -{\left (b c - a d\right )} \cos \left (2 \, b x + 2 \, a\right )\right )} \log \left (-\frac{1}{2} \, \cos \left (2 \, b x + 2 \, a\right ) - \frac{1}{2} i \, \sin \left (2 \, b x + 2 \, a\right ) + \frac{1}{2}\right ) + 2 \,{\left (b d x + a d -{\left (b d x + a d\right )} \cos \left (2 \, b x + 2 \, a\right )\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) + i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) + 2 \,{\left (b d x + a d -{\left (b d x + a d\right )} \cos \left (2 \, b x + 2 \, a\right )\right )} \log \left (-\cos \left (2 \, b x + 2 \, a\right ) - i \, \sin \left (2 \, b x + 2 \, a\right ) + 1\right ) + 2 \, d \sin \left (2 \, b x + 2 \, a\right )}{4 \,{\left (b^{2} \cos \left (2 \, b x + 2 \, a\right ) - b^{2}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \left (c + d x\right ) \cot ^{3}{\left (a + b x \right )}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (d x + c\right )} \cot \left (b x + a\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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